In triangle ABC if AC = BC angle A = 55° then angle C is
A 55⁰
B 45⁰
C 35⁰
D 70⁰
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In a △ABC, by angle sum property, sum of angles of a triangle is 180⁰
∴∠ABC+∠BCA+∠CAB=180⁰
Given : ∠A=∠CAB=55⁰
and ∠B=∠ABC=40⁰
∴55∘+40∘+∠BCA=180⁰
∴∠BCA=180∘−95∘ =85⁰
Therefore, ∠BCA=∠C=85⁰
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