Question

in triangle ABC . if AD=DB and angle B is right angle . detemine (1)Sinθ (2) Tanθ (3) Sin^2θ + Cos^2θ​

Answer 1

Step-by-step explanation:

AD= DB = a/2

CB = √b²- a²

CD= √ a²/4 +b² - a²

1) sinø = DB/CD

= a/2 / √a²/4 + b²- a²

= a/ √- 3a²+4b²

2) tanø = DB/CB

= a/2 /√b²- a²

3) sin²ø + cos²ø = (a²/ -3a² + 4b²) + ( 4b²- 4a²/ 4b²- 3a²)

= a² + 4b²-4a²/ 4b²- 3a²

= 4b² - 3a²/ 4b²- 3a²

= 1