in triangle abc if ad is a median prove that AB square + AC square is equal to 2 AD square + half BC square
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I think that
according to Pythagoras theorem,
AB² = AD² + BD² ..... (1)
from ∆ADC ,
according to Pythagoras theorem,
AC² = AD² + DC² ...... (2)
\because AD is median.
so, BD = DC .......(3)
from equations (1) , (2) and (3),
AB² + AC² = AD² + AD² + BD² + BD²
AB² + AC² = 2(AD² + BD²)
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