Question

In triangle ABC,if AD is perpendicular bisector of BC,then triangle ADC is​

Answer 1

Step-by-step explanation:

∆ADC is similar to ∆ABC.

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Answer 2

Step-by-step explanation:

Given: AD is the perpendicular bisector of BC. 

To Prove:△ABC is an isosceles triangle. i.e,AB=AC

Proof: In △ADB and $$\triangle{ADC}, 

AD=AD(Common)

△ADB=△ADC. ( each 90∘) 

⇒BD=CD 

where AD is the perpendicular bisector 

Therefore, △ADB≅△ADC ( by SAS congruence rule) 

⇒AB=AC (by CPCT) 

So,△ABC is an isosceles triangle. 

Note: In Congruent Triangles corresponding parts are always equal and we write it in short CPCT i e, corresponding parts of Congruent Triangles.