In triangle ABC, if AD is the bisector of angle A show that AB is greater than BD
Answers
Step-by-step explanation:
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Answer:
If AD is the bisector of ∠A of triangle ABC, show that AB>DB. Given :AD is the bisector of ∠A of triangle ABC . ∠BDA is the exterior angle of the ∆DAC. → AB > BD In a triangle sides opposite to greater angle is greater..