Question

In triangle ABC, if AD is the bisector of Z angle A, show
that AB > BD and AC > DC.
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Answer 1

Answer:

There ain't no answer its called a proof.

Step-by-step explanation:

Given that, AD is the bisector of ABC

hence, <DAB = <DAC

<BDA is exterior angle of triangle DAC

hence, angle BDA >angle DAC

or Angle BDA >Angle DAB

since , DAB = DAC

AB greater than BD in triangle sides opposite to greater angle is greater.