Math, asked by chinmallisanjana, 10 months ago

In triangle ABC, if angle A=100°,AD bisects angle A and AD perpendicular BC. Then, angle B =?

Answers

Answered by mropmeena2881
6

Answer:

the answer is angle B= 40 degree

Step-by-step explanation:

in the triangle ABC

angle A=100 degree

now, as AD bisects Angle A

so angle DAB=angle DAC (each 50 degree as AD bisect angle BAC)

and angle ADB=angle ADC (each 90 degree as AD is perpendicular to BC)

now, in triangle ABD formed

angle ADB+angle DAB+angle ABD=180 degree (angle sum property of triangle)

50+90+angle ABD=180 degree

angle ABD=180-(50+90)

angle ABD=180-140=40 degree

thus, angle ABD or angle B=40 degree

ans. 40 degree

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