In triangle ABC, if angle A=100°,AD bisects angle A and AD perpendicular BC. Then, angle B =?
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Answer:
the answer is angle B= 40 degree
Step-by-step explanation:
in the triangle ABC
angle A=100 degree
now, as AD bisects Angle A
so angle DAB=angle DAC (each 50 degree as AD bisect angle BAC)
and angle ADB=angle ADC (each 90 degree as AD is perpendicular to BC)
now, in triangle ABD formed
angle ADB+angle DAB+angle ABD=180 degree (angle sum property of triangle)
50+90+angle ABD=180 degree
angle ABD=180-(50+90)
angle ABD=180-140=40 degree
thus, angle ABD or angle B=40 degree
ans. 40 degree
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