in triangle ABC if angle A=120 and AB = AC find angle B and C
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it's an isosceles angled triangle
AB=AC
therefore ACB=ABC=x
120+x+x=180
2x= 180-120
x= 60/2
x=30
AB=AC
therefore ACB=ABC=x
120+x+x=180
2x= 180-120
x= 60/2
x=30
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