Question

. In triangle ABC, If angle A=(2x-5)°, angle B=(5x+5)° and angle C=(3x+50)°, then find the value of angleA, angle B, angle C ​

Answer 1

Answer:

The sum of all the 3 angles of a triangle is 180degree.

So, angle A + angle B+ angle C =180

(2x-5)+(5x+5)+(3x+50=180

10x+50=180

10x=180-50

10x=130

x=130/10

x=13

Now, angle A =(2x-5)=2 x 13-5=26-5=21

angle B=(5x+5)=5 x 13+5=65+5=70

angle C=(3x+50)=3 x 13+50=39+50=89

Therefore answer is

angle A=21

angle B=70

angle C=89