Math, asked by csonsakia, 11 months ago

In triangle ABC if angle A= 2x-5 angle B= 5x+5,angle C= 3x+50, then find the all angles​

Answers

Answered by pankajdagar
2

Answer:

angle A + angle B + angle C = 180(angle sum property)

2x-5+5x+5+3x+50=180

10x + 50 = 180

10x=180-50

10x=130

x= 130/10

x = 13

angle A = 2x 13 -5

= 26 - 5

= 21

angle B = 5 x 13 + 5

= 65 + 5

= 70

angle c = 3x 13 +50

= 39 +50

= 89

Answered by rabab0604
0

Answer:

Step-by-step explanation:

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