in triangle ABC, if angle A = 3 Angle B and angle C = 2 ,Angle B. find all the three angle of triangle ABC.
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Answered by
10
Let angle A = x
Angle B = y
As mentioned in the question angle C = 3 angle B = 3y
Angle C is also given as 2(Angle A + Angle B)
= 2(x+y)
So,
3y = 2(x+y)
y = 2x
So angle C = 3y = 6x
We know that sum of all the 3 angles in a triangle = 180deg
Therefore,
Angle A+ Angle B + Angle C = 180
x+ 2x+ 6x = 180
x = 20
Hence Angle A = 20
Angle B = 40
Angle C = 120
Answered by
3
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