Question

In triangle ABC if angle A =45? and angle B=70? determine the shortest and largest sides of the triangle ABC; In triangle ABC if angle A =45? and angle B=70? determine the shortest and largest sides of the triangle ABC

Answer 1

let angle c be x
45+70+x=180
115+x=108
x=65
angle B is largest and hence AC will be longest side. Angle A is smallest and hence BC will be shortest side

Answer 2

Answer:

We have,

1st angle = 45°

2nd angle = 70°

3rd angle = ?

Let's find 3rd angle of triangle.

$\\ \qquad \sf \angle \: A = 45 \: \: \: and \: \: \: \angle \: B = 70 \\ \\ \\ \therefore \: \: \sf \angle \: A + \angle \: B + \angle \: C = 180 \\ \\ \\ \implies \sf45 + 70 + \angle \: C = 180 \\ \\ \\ \implies \sf \angle \: C = 180 - 115 \\ \\ \\ \implies \boxed{ \sf \angle \:C = 65}$

Since the side opposite to the greatest side is largest. Therefore, side AC is largest.

The side opposite to the least angle is the smallest. So, side opposite to A i.e BC is the smallest.