In triangle ABC , if angle A = 50 o , , angle B = 60 o ,determine the shortest and longest sides of the triangle
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A=50
B=60
A+B+C=180
50+60+C =180
110+C =180
C =180-110
C=70
angle opposite to longest is longest side i.e
side opposite to <C is AB is biggest
shortest side is opposite to <A is BC is shortest
B=60
A+B+C=180
50+60+C =180
110+C =180
C =180-110
C=70
angle opposite to longest is longest side i.e
side opposite to <C is AB is biggest
shortest side is opposite to <A is BC is shortest
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