Question

In triangle ABC if angle A +angle B = 120 degree and angle B+ angle C = 100 degree, find the angles of the triangle

Answer 1

In any triangle, the sum of all 3 angles is 180° . So,

angleA+angleB+angleC = 180°

108°+angle C= 180° (since angleA+angleB=108°).

angle C= 180°- 108°= 72°

angleA+ 130°=180°(since angleB+angleC=130°).

angle A= 180°- 130°= 50°

angle B= 180°-(72°+50°)= 58°

Answer 2

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In any triangle, the sum of all 3 angles is 180° . So,

angleA+angleB+angleC = 180°

108°+angle C= 180° (since angleA+angleB=108°).

angle C= 180°- 108°= 72°

angleA+ 130°=180°(since angleB+angleC=130°).

angle A= 180°- 130°= 50°

angle B= 180°-(72°+50°)= 58°