In triangle ABC, If angle A + Angle B = 65 degree, angle B + angle C = 140 degree, then find the value of angle B.
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2
a+b=65,b+c=140
a+b+c=180
65+c=180
c=115
b+c=140
b=140-115=25
a+b+c=180
65+c=180
c=115
b+c=140
b=140-115=25
Answered by
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in triangle ABC,
∠C= 180°-(<A +<B)
∠C=180°-65°
∠C=115°
∠B=140°-115°=25°
∠B=25°
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