in triangle abc if angle A is equals to 5 Angle B and angle C is equals to 3 Angle B find all the three angles of triangle ABC
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Answer:
let angleB be x
angle A= 5x
angle C=3x
sum of all angles =180°
A+B+C=180°
5x + x + 3x =180°
9x=180°
x=180°÷9
x=20°
A=5×20=100°
B=20°
C=3×20°=60°
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