In triangle abc, if angle A minus Angle B = 15 degree, angle B minus angle C = 30 degree, find angle a, angle b and angle c
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angle A=A, angle B=B, angle C=C
given,
A-B=15°→A=15+B
B-C=30°→C=B-30
by angle sum property of triangle
A+B+C=180°
B+(15+B)+(B-30)=180
3B-15=180
3B=180+15
B=195/3
B=65°
So,
A=65+15=80°
B=65°
C=65-30=35°
given,
A-B=15°→A=15+B
B-C=30°→C=B-30
by angle sum property of triangle
A+B+C=180°
B+(15+B)+(B-30)=180
3B-15=180
3B=180+15
B=195/3
B=65°
So,
A=65+15=80°
B=65°
C=65-30=35°
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1
Answer:
In triangle abc, if angle A minus Angle B = 15 degree, angle B minus angle C = 30 degree, find angle a, angle b and angle c.
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