Question

in triangle abc if angle A minus angle b is equal to 40 degree and Angle B minus angle C is equal to 10 degree find the measure of angle A and Angle B and angle C




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Answer 1

let angle A=x

angle B=x-40°

angle C=x-50°

in triangle sum of all angles is 180°

x+x-50°+x-40°=180°

3x-90°=180°

3x=270°

x=90°

angle A=90°

B=50°

C=40°

Answer 2

Answer:

ANSWER

In the △ABC according to the given condition we have ∠B−∠C=30 o

⇒∠B=30 o+∠C

∠A−∠B=15 o

⇒∠A=15 o+∠B=45 o+∠C

Now, using the property that sum of all the interior angle of a triangle is 180 owe get

∠A+∠B+∠C=180 o

⇒45 o+∠C+30 o+∠C+∠C=180o

⇒3∠C=105 o

⇒∠C=35o

∴∠A=80o ,∠B=65 o,∠C=35o

Step-by-step explanation: