In triangle ABC,if angle A plus angle B equal to 180 degree and angle B plus angle C equal to 130 degree.find angle A,angle B,and angle C
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A+B+B+C=180+130(by combining both)
(A+B+C)+B=310
180+B=310
B=130
Now A=180-B=180-130=50
B=130
C=0
(A+B+C)+B=310
180+B=310
B=130
Now A=180-B=180-130=50
B=130
C=0
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I have thought that your question my be the second figure in which I have answered.
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