In triangle ABC, if angle AB = 4 cm, angle A = 50° and angleB = 80°, then the length of BC is :
a.7cm
b.6cm
c.4cm
d.3cm
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Answer:
C- 4cm
Step-by-step explanation:
Let,
angle C=x°
In a triangle
angle A+angle B +angle C =180°
50°+80°+x°= 180°
130°+x° =180°
x°=180-130
x°=50°
hence,
triangle ABC is an isosceles triangle
AB=BC
AB=BC=4cm
therefore BC=4cm
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