Question

in triangle ABC if angleA +angleB =108 and angle B +angle C =130 find angle A B and C

Answer 1

angle A +angle B=108
x + x. =108
2x =108
x=108/2
x=54
Therefore,angle B =54

Angle B +Angle C = 130
54. +. x. =130
x=130-54
x=76
Therefore,Angle C =76
Angle A =54
Angle B =54

Hope it helps

Answer 2

hope it works
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