Question

in triangle ABC,if angleA+angleB=108°and angleB+angleC=130°,find angleA,angleB&anglec

Answer 1

Answer:

<A=50°,<B=68°,<C=72°

Step-by-step explanation:

<A+<B+<C=180°

108°+<C=180

<C=72°

<A+<B+<C=180°

<A+130°=180°

<A=50°

<A+<B+<C=180°

50°+<B+72°=180°

<B=68°

Answer 2

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