In triangle abc if b=root 3 ,c=1,angle a=30 find a
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pls clear the question you posted.
Answered by
22
Answer:
Step-by-step explanation:
Let start ,cosA=b²+c²-a²/2bc. Then cos30=(root3)²+1²-a²/2root3*1. Then root3/2=3+1-a²/2root3 on solving we get a=1 thanks
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