Question

in triangle abc if bc =12cm ac =10cm and perimeter of a
triangle is 32
1) find length of AB
2) area of triangle ABC​

Answer 1

HEY MATE

1 the length of AB

perimeter of the triangle ABC=AB +BC+AC

= 12+10+AB=32

=22+ AB= 32

AB=10cm

2 AREA OF TRIANGLE

S = 32cm

areaof triangle =

$\sqrt{(s - a)( s- b)( s- c)}$

$\sqrt{(32 - 12)(32 - 10)(32 - 10)}$

$\sqrt{20 \times 22 \times 22}$

$\sqrt{9680}$

$98 .38 {cm}^{2} appox$

I hope it helps u