In triangle ABC if BC = 4 and AC = 3, and cos C = -1/2 what is the length of AB ?
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We have, AB = 4 and BC = 3.
By Pythagoras theorem, we have
AC2=AB2+BC2
⇒AC=AB2+BC2
⇒AC=42+32=25=5
When we consider the t-ratios of ∠A, we have
Base = AB = 4, Perpendicular = BC = 3, Hypotenuse = AC = 5.
∴sinA=ACBC=53,cosA=ACAB=54,tanA=ABBC=43
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