In triangle abc if bc is parallel to de then the value of x
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Given : bc is parallel to de
To Find : Value Of DE
Solution:
BC || DE
=> ∠ADE = ∠ABC ( corresponding angles )
∠AED = ∠ACB ( corresponding angles )
∠A = ∠ A common angle
Δ ADE ≈ Δ ABC
=> AD/AB = DE/ BC
=> AD/(AD + DB) = DE/BC
=> 3/(3 + 2) = DE/10
=> DE = 6
Value of DE = 6
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