In triangle ABC ,if bisectors of <ABC and < ACB intersect at O at an angle
of 120 0 . Then find the measure of <A.
Answers
Answered by
0
Answer:
Given:
Here in A ABC, the bisectors of ZABC and ZACB intersect at O.
Also as shown in the figure, <BOC = 120°
So here, using the corollary, if the bisectors of ZABC and ZACB meet at a point O, then
ZBOC= 90+ZA
Therefore in A ABC,
ZBOC= 90+ZA
120 - 90+ZA 2
120- 90 ZA
30 = A -
ZA = 30 × 2
ZA = 60°
Answered by
0
Answer:
In ΔBQC
∠BOC + ∠OBC + ∠OCB = 180°
∠B + ∠C = 120° (i)
In ΔABC
∠A + ∠B + ∠C = 180°
∠A + 120° = 180°[From (i)]
∠A = 60°
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