CBSE BOARD X, asked by sujithcn4527, 8 months ago

IN TRIANGLE ABC, IF DE IS PARALLEL TO BC SUCH THAT A-D-B AND A-E-C AD=4, DB=8, EC=16 THEN AE IS *

Answers

Answered by bijaykumar45408

0

Answer:

AE=8

Explanation:

in triangle ABC DE parallel to BC so AD÷BD=AE÷EC so 4÷8=AE÷16 in this process we get the answer is 8

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