Question

In triangle ABC, if L and M are the points on AB and AC, respectively such that LM is parallel BC. BM and LC interested at O. Prove that ar (LOB) = ar (MOC)​

Answer 1

Answer:

We know on same base and same parallel area are equal

Answer 2

Answer:

Step-by-step explanation:

angle LOB = angle MOC ( vertically opposite angle)

LB = MC

since midpoint divides into equal halves

angle LBO = angle MCO

since BM and CL bisects ABC and ACB into two equal halves

therefore LOB = MOC