In triangle abc if r1=3 r2=10 r3=15 then c
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Given: r1 = 3, r2 = 10, r3 = 15
To find: Value of c?
Solution:
- Now we have given the values of r1, r2 and r3, so in solution of triangles, we know that:
- 1 / r = 1 / r1 + 1 / r2 + 1 / r3
1 / r = 1 / 3 + 1 / 10 + 1 / 15
1 / r = 10 + 3 + 2 / 30
1 / r = 15 / 30
r = 2
- Also, we know that:
- Δ² = r x r1 x r2 x r3
Δ² = 2 x 3 x 10 x 15
Δ² = 900
Δ = √900
Δ = 30
- Now, r = Δ/s
s = Δ/r
s = Δ / r = 30 / 2 = 15
r3 = Δ / (15 - c)
15 = 30 / (15-c)
15 - c = 2
c = 15 - 2
c = 13
Answer:
So the value of c is 13.
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