Question

in triangle ABC if r¹=8,r²=12,r³=24 then find the value of sinB​




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Answer 1

Answer:

16

This is your answer ☝

Step-by-step explanation:

In Triangle ABC, r1=8,r2=12,r3=24

1/r = 1/r1 + 1/r2 + 1/r3

1/r = 1/8 + 1/12 + 1/24

1/r = 3+2+1/24

1/r = 1/4

r = 4

= square root rr1 r2 r3 = square root 4*8*12*24 = 96

r = /s = 96/s

96/s = 4

S = 24

r1 = /s-a = 96/24-a = 8

96/24-a = 8

12 = 24-a

a = 12

Similarly using r2 = 96/24-b=12 and r3 = 96/24-c

we get b = 16

c = 20