In triangle ABC, if sin A=8/17, what is cos B?
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cos b is 17/15 where 17 is Base and 15 is perpendicular 15 came by pythagoras theorem as by sin a we know the p and h
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sin A = 8/17 -----(1)
A+B=90
B = 90 - B
cos B = cos (90-A)
cos B = sin A
cos B = 8/17 from (1)
A+B=90
B = 90 - B
cos B = cos (90-A)
cos B = sin A
cos B = 8/17 from (1)
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