in triangle ABC if tan A. tanB =1 then find value of A+B
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Answer:
A+B=90°
Step-by-step explanation:
we know that
tan(A+B)={ tanA+tanB}/(1-tanAtanB)
={ tanA+tanB}/(1-1)
=( tan A+tanB) / 0=∞
thus A+B=90°
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