Question

In triangle ABC is an isosceles triangle in which angle C=90 degree. If BC=4cm find AB​

Answer 1

Hello,

Given :-

Triangle ABC is a isosceles triangle and Angle C is 90 degrees.

Also,

AC = 6 cm

Now,

Please refer the above attachment for the figure.

Now,

AC =BC

(triangle is isosceles)

So,

BC = 6 cm

Also,

The triangle is a right triangle

applying Pythagoras theorem to obtain the value of AB

So now

So

Putting the values

So,

The value of AB is 6root2 cm.

Hope this will be helping you ✌️ ..................

Answer 2

Answer:

Required length of AB is $4 \sqrt{2} \:c m$.

Step-by-step explanation:

Given,ABC is isosceles triangle and this triangle right-angled at C

$[\angle C = 90\degree]$

Length of AC = 4cm

This is a isosceles triangle.

We can say AC=BC

AB = ?

By Pythagoras theorem,

${AB}^{2} = {AC}^{2} + {BC}^{2}$

$AB = \sqrt{AC^2 + BC^2}$

$AB = \sqrt{4^2 + 4^2}$

$AB = \sqrt{16+ 16}$

$AB = \sqrt{32} = \sqrt{2 \times 2 \times \times 2 \times 2}$

$AB = 2 \times 2 \sqrt{2} = 4 \sqrt{2}$

Required length of AB is

$4 \sqrt{2} \:c m$