Question

In triangle, ABC is an Isosscoles right-angled triangle in which angle A=90 degree, find angle B

Answer 1

Answer:

Given,

\DeltaABC is an isosceles triangle

Right-angled at C [\angle C = 90\degree]

AC = 4cm

AB = ?

\DeltaABC = isosceles \Rightarrow AC = BC = 4 cm

AB = \sqrt{AC^2 + BC^2}

AB = \sqrt{4^2 + 4^2}

AB = \sqrt{16+ 16}

AB = \sqrt{32}

AB = 4\sqrt{2}