Question

In triangle ABC is isosceles with AB=AC=7.5 cm and BC=9 cm (Fig 11.26). The height
AD from A to BC, is 6 cm. Find the area of AABC. What will be the height from C
to AB i.e., CE?​

Answer 1

Answer:

area of the triangle ABC

=1/2.base.height

=1/2.BC.AD

=1/2.9.6 sq cm

=27 sq cm

if CE is the height,then AB is the base

so,

1/2.AB.CE= 27

=> 1/2×7.5×CE=27

=> CE=27×2/7.5

=> CE=27×10×2/75

=9×2×2/5

=36/5

=7.2

so, CE =7.2 cm

Answer 2

Answer

In ΔABC, AD=6cm and BC=9cm

Area of triangle=

2

1

×base×height=

2

1

×BC×AD

=

2

1

×9×6=27 cm

2

Again, Area of triangle=

2

1

×base×height=

2

1

×AB×CE

⇒27=

2

1

×7.5×CE

⇒ CE=

7.5

27×2

⇒ CE=7.2cm

Thus, height from C to AB i.e., CE is 7.2cm.

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