In triangle ABC is midpoint of the median ad and be produced meets side AC at point Q show that be:eq =3:1
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Let's take point Y on seg AC such that DY | | BX.
As D is a midpoint of BC, by converse of midpoint theorem, XY=YC.
Applying midpoint theorem in triangle CDY, BX=2DY.
As E is a midpoint of AD & EX | | DY,
AX=XY.
Applying midpoint theorem in triangle DAY, EX= DY/2
BE/EX = BX-EX / EX
= 2DY - DY/2 / DY/2
= 3DY / 2 * 2/YD
= 3DY/DY
= 3:1.
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