Math, asked by alexrajking, 1 month ago

in triangle ABC it is given that AB=6cm AC=8cm and AD is the bisector of <A.Then ,BD:DC=?​

Answers

Answered by jeevithdeepak
9

Answer:

3:4

Step-by-step explanation:-

by angle bisector theorem,

bd/dc=ab/ac

==>bd/dc=6/8

==>bd/dc=3/4

so,

bd:dc = 3:4

HOPE IT HELPS U :)

Answered by Anonymous
2

Given:

  • AB = 6cm
  • AC = 8cm
  • AD is the bisector of ∠A

To Find:

  • The ratio of BD:DC.

Solution:

  • Let us construct a triangle using the given data.
  • From the ΔABC we can come to few conclusions,
  • In ΔABD and ΔACD,
  • we have ∠BAD = ∠CAD
  • So, \frac{BD}{DC}  = \frac{AB}{AC}  ( By basic proportionality theorem)
  • Substitute the values in the equation formed.
  • ⇒  \frac{6}{8}  = \frac{3}{4}
  • Hence,
  • BD/DC = 6/8 ⇒ BD/DC = 6:8 = 3/4
  • ⇒BD/DC = 3/4
  • ⇒ BD:DC = 3:4

∴The value of BD:DC = 3:4

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