In triangle ABC, it
then the
а angle
B=90⁰, AB = 12 cm and B C = 9cm value of cos C is?
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Step-by-step explanation:
triangle is right angled at B so, use pythagoras formula
AC² = AB² + BC²
AC² = 12² + 9²
AC = 13
cosC=BC/AC
= 9/13
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