Question

IN Triangle ABC,LA-70⁰,LB-45⁰.Find The Measuere of LC
​

Answer 1

Step-by-step explanation:

We have,

1st angle = 45°

2nd angle = 70°

3rd angle = ?

Let's find 3rd angle of triangle.

\begin{gathered}\\ \qquad \sf \angle \: A = 45 \: \: \: and \: \: \: \angle \: B = 70 \\ \\ \\ \therefore \: \: \sf \angle \: A + \angle \: B + \angle \: C = 180 \\ \\ \\ \implies \sf45 + 70 + \angle \: C = 180 \\ \\ \\ \implies \sf \angle \: C = 180 - 115 \\ \\ \\ \implies \boxed{ \sf \angle \:C = 65} \\ \\\end{gathered}

∠A=45and∠B=70

∴∠A+∠B+∠C=180

⟹45+70+∠C=180

⟹∠C=180−115

⟹

∠C=65

Since the side opposite to the greatest side is largest. Therefore, side AC is largest.

The side opposite to the least angle is the smallest. So, side opposite to A i.e BC is the smallest.

Answer 2

Answer:

by the angle sum property

sum of all angles of a triangle =180

70+45+LC=180

115+angle c = 180

angle C = 180-115

angle C= 65.