In triangle ABC , LA + LB = 110° , LB + LC = 132.
find LA ,LB and LC
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GIVEN LA +LB = 110°------- (1)
LB +LC = 132 ------(2)
BY ANGLE SUM PROPERTY
LA + LB + LC = 180° ------(3)
putting the value of equation (1)
LA +LB+LC = 180°
110° + LC = 180°
LC = 180° - 110°
LC = 70°
NOW , PUT THE VALUE OF LC IN EQUATION (2)
LB +LC = 132°
LB + 70°=132
LB = 132° - 70°
LB = 62°
WE HAVE THE VALUE OF LB AND LC , SO WE CAN FIND THE VALUE OF LA BY MANY WAYS...
putting the value of LB in equation (1)
LA+LB = 110°
LA = 110° - LB
LA = 110° - 62°
LA = 48°
OR
LA +LB +LC = 180°
LA + 62° + 70° = 180°
LA = 180° - 132°
LA = 48°
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