In triangle ABC LA-Lc and BC = 4 then,
the perimeter of triangle ABC is
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Answer:
Angle A = angle C
therefore this angle is right angled triangle
angleA=angle C=45
angle B=90
by 45-45-90 therem
AB=1/underoot2×AC---(side opposite 45 angle)
AB=1/underoot 2×5
AB=5/underoot 2
AB=7.07
perimeter=AB+BC+AC
Perimeter=7.07+4+5
perimeter= 16.07
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