Math, asked by krishsurve183, 3 months ago

In triangle ABC LA-Lc and BC = 4 then,
the perimeter of triangle ABC is​

Answers

Answered by sreegopalshenoy
0

Answer:

Angle A = angle C

therefore this angle is right angled triangle

angleA=angle C=45

angle B=90

by 45-45-90 therem

AB=1/underoot2×AC---(side opposite 45 angle)

AB=1/underoot 2×5

AB=5/underoot 2

AB=7.07

perimeter=AB+BC+AC

Perimeter=7.07+4+5

perimeter= 16.07

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