Question

in triangle ABC, LC = 2LB and the Bisector of LC intersects
AB at D. PROVE THAT
AD/DC = CA/CB​

Answer 1

Answer:

Step-by-step explanation:

AΔABC ∼ ΔABD.

Thus,

AB : AD = BC : BD

In ΔBDC,

∠DBC = ∠C

⇒DC = BD ...(2) (sides opposite to equal angles are equal)

Using (2) in (1), we get

AB : AD = BC : DC

⇒ DC : AD = BC : AB