Math, asked by ritikaverenkar, 11 months ago

In triangle ABC, LC=90
tanA= 1/3
find
Sin A CosB + Cos A SinB

Answers

Answered by Anonymous

1

Step-by-step explanation:

Step-by-step explanation:

tanA=BC/AB=‌1/root 3

Thus BC=1 AB=root 3

In triangle ABC,

AB2+BC2=AC2

Thus AC=2(BY PYTHAGORAS THEORM)

SinAcosC+cosAsinC=1/2*1/2+root3 /2*root3/2

=1/4+3/4

=4/4

=1

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