Question

In triangle abc, line xy is parallel to side bc, it intersects side ab in x and side ac in line, if the line by divides this angle xyc​

Answer 1

As XY∣∣BC

∠XYB=∠CBY (1) ( Alternate interior angles)

BY bisects ∠XYC

∠XYB=∠CYB

by (1) ∠CBY=∠CYB

BC=CY ( side opposite to equal angles are equal)

I hope you like my answer!