in triangle abc, <c=90°, 3cot A=4, sinB=?
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1
Answer:
cotA=3/4
cot=p/b
p=3
b=4
h^2=p^2+b^2
sin=3^2+4^2
=9+16
=25
h^2=25
h=root 25
h=5
sin=p/h
3/5
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