Question

In triangle ABC, M and N are midpoints of AB and AC, and NP || AB.
i) Prove that BMNP is a parallelogram

Plz help !

Answer 1

Answer:

onsider the triangle ABC, M and N are the midpoints of the sides AB and AC respectively.

Let AP be the altitude from the vertex A to the side BC.

The line joining the midpoints of AB and AC meet the altitude AP at O.

Required to prove that AO = OP.

So, we have to prove that AO = ½AP

In triangle ABC.

M and N are the midpoints of the sides AB and AC.

So, we have

AM = ½AB; AN = ½ AC

According to the Midpoint Theorem,

MN = ½ BC

So, ΔABC ~ ΔAMN

⇒ Area(AMN) / Area(ABC) = MN2 / BC2

= ( BC/2 )2 / BC2

= 1/4

= AO2 / AP2

So,

AO/AP = 1/2

AO = ½ AP

:

Answer 2

Answer = 23 cm

hope it helps...