Question

In triangle ABC,m angle b=90°, m angle C=30°, m angle A=60° and AB=6 cm Then find AC=?​

Answer 1

In ∆ ABC , angle B=90° , angle C= 60° , angle A=30° and BC=12 cm. , applying

sine rule:-

AB/sinC = BC/sinA = CA/sinB.

or. AB/sin60° = 12/sin30°= CA/sin90°.

or. 2.AB/√3. = 2.12/1= CA/1.

or. AB = 12√3 cm. , CA(hypotenuse) = 24cm.

Area of triangle ABC = (1/2)×AB×BC = (1/2)× 12√3×12

= 72√3 cm^2. = 124.704 cm^2.