Question

In triangle abc measure angle acb = 90 degree, line cd perpendicular to line ab and measure angle acd= 45 degrees. find cd if bc = 3 in.

Answer 1

Answer:

given angle CDB=90°, angle DCB=ACB/2=90°/2=45°

then angle CBD=180°-(45°+90°)=45°

Now,In right angled triangle CDB,

tan B=CD/BC. (tan=Perpendicular/Base

tan45°=CD/3

1=CD/3

CD=3

you should know the value of angles of trigonometric ratios for these questions