In triangle ABC measure of angle CAB is an obtuse. P is the circumcentre of triangle ABC. Prove that angle PBC=angle CAB -90
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∠CAB is an obtuse angle.
Let P be the circumcentre of the triangle ABC.
Radii of the same circle are equal.
⇒ PA = PB = PC
Two angles are equal in isosceles triangle.
In
Two angles are equal in isosceles triangle.
– – – – (1)
Angle opposite to equal sides are equal.
– – – – (2)
Add (1) and (2), we get
Since
Hence proved.
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